A) more reactance
B) less reactance
C) zero reactance
D) infinite reactance
Correct Answer: B
Solution :
Capacitive reactance is given by \[{{X}_{C}}=\frac{1}{\omega C}\] where C is capacitance and co the angular frequency.\[(\omega =2\pi f)\] \[\therefore \] \[{{X}_{C}}=\frac{1}{2\pi fC}\] \[\Rightarrow \] \[{{X}_{C}}\propto \frac{1}{f}\] Hence, when frequency\[f\]increases capacitive reactance decreases.
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