question_answer

\[Ph-C\equiv C-C{{H}_{3}}\xrightarrow[{}]{H{{g}^{2+}}{{H}^{+}}}A\] The product A is:

A)                              

B)  

C)                          

D)  

Correct Answer: A

Solution :

                \[Ph-C\equiv C-C{{H}_{3}}\xrightarrow[{}]{H{{g}^{2+}}/{{H}^{+}}}Ph-\underset{\begin{smallmatrix}  | \\  OH \end{smallmatrix}}{\mathop{C}}\,=CH-C{{H}_{3}}\]