J & K CET Medical J & K - CET Medical Solved Paper-2000

  • question_answer
    Which of the following will not undergo Hell-Volhard-Zelinsky reaction?

    A)  Acetic acid

    B)  Formic acid

    C)  Propionic acid

    D)  2-methyl propionic acid

    Correct Answer: B

    Solution :

                    The aliphatic carboxylic acids containing \[\alpha -\]hydrogen react with\[C{{l}_{2}}\]or\[B{{r}_{2}}\]in the presence  of red  phosphorus  to  give\[\alpha -\]haloacids.   This   reaction   is   called Hell-Volhard-Zelinsky reaction. \[\overset{\alpha }{\mathop{C}}\,{{H}_{3}}COOH\xrightarrow{C{{l}_{2}},P}\underset{\begin{smallmatrix}  monochloroacetic \\  \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,acid \end{smallmatrix}}{\mathop{ClC{{H}_{2}}-COOH}}\,\xrightarrow{C{{l}_{2}},P}\] \[\underset{\begin{smallmatrix}  dichloroacetic \\  \,\,\,\,\,\,\,\,\,\,\,\,acid \end{smallmatrix}}{\mathop{C{{l}_{2}}-CH-COOH}}\,\xrightarrow{C{{l}_{2}},P}\underset{\begin{smallmatrix}  trichloroacetic \\  \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,acid \end{smallmatrix}}{\mathop{CC{{l}_{3}}-COOH}}\,\] \[HCOOH\]does not give Hell-Volhard Zeiinsky reaction due to absence of\[\alpha -H\]atom.


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