A) \[50{}^\circ C\]
B) \[45{}^\circ C\]
C) \[30{}^\circ C\]
D) \[60{}^\circ C\]
Correct Answer: B
Solution :
The angle of inclination is given by \[\tan \theta =\frac{{{v}^{2}}}{rg}\]where v is the velocity, r the radius of circular track and g the acceleration due to gravity \[velocity(v)=\frac{dis\tan ce(2\pi r)}{time}=\frac{34.3}{\sqrt{22}}\] \[\therefore \] \[\tan \theta =\frac{{{v}^{2}}}{rg}={{\left( \frac{34.3}{\sqrt{22}} \right)}^{2}}\times \frac{2\pi }{34.3\times 9.8}\] \[\Rightarrow \] \[\tan \theta =1\] \[\Rightarrow \] \[\theta ={{45}^{o}}\]
You need to login to perform this action.
You will be redirected in
3 sec
