A) \[J{{K}^{-1}}mo{{l}^{-1}}\]
B) J
C) JK
D) \[Jmo{{l}^{-1}}\]
Correct Answer: A
Solution :
From ideal gas equation \[PV=\mu RT\] \[\Rightarrow \] \[R=\frac{PV}{\mu T}\] \[\therefore \]Unit of \[R=\frac{Unit\text{ }pressure\times unit\,of\,volume}{mol\times unit\text{ }of\text{ }temperature}\] \[=\frac{newton-\text{ }metr{{e}^{-2}}\times metr{{e}^{3}}}{mol-K}\] \[=\frac{newton-metre}{mol-K}\] \[=\frac{joule}{mol-K}\] \[=(J-mo{{l}^{-1}}{{K}^{-1}})\]
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