A) 60
B) 32
C) 34
D) 64
Correct Answer: A
Solution :
The number of possible elements would be \[E=\sum\limits_{n=1}^{4}{2{{n}^{2}}}=2\sum\limits_{n=1}^{4}{[{{1}^{2}}+{{2}^{2}}+{{3}^{3}}+{{4}^{2}}]}\] \[E=2[1+4+9+16]=2\times 30=60\]
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