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J & K CET Medical J & K - CET Medical Solved Paper-2000

  • question_answer
    The ratio of radii of nuclei \[_{13}^{27}\]Al and \[_{52}^{152}Te\] is approximately:

    A)  6 : 10                                    

    B)  13 : 52

    C)  40 : 177                                               

    D)  14 : 7

    Correct Answer: A

    Solution :

                    The radius of a nucleus of atomic number A is given by \[R={{R}_{0}}{{A}^{1/3}}\] where\[{{R}_{0}}\]is Bohrs radius. Given, \[{{A}_{1}}=27,\]                \[{{A}_{2}}=125\] \[\therefore \]  \[\frac{{{R}_{1}}}{{{R}_{2}}}={{\left( \frac{27}{125} \right)}^{1/3}}=\frac{3}{5}=\frac{6}{10}\]


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