A) 4 times
B) 2 times
C) halved
D) remains unchanged
Correct Answer: A
Solution :
The self-inductance of a solenoid of length\[I,\] number of turns N and area A is \[L=\frac{{{\mu }_{0}}{{N}^{2}}A}{l}\] where\[{{N}^{2}}=2\text{ }N,\]then \[{{L}_{2}}=\frac{{{\mu }_{0}}{{(2N)}^{2}}A}{l}=4L\] Hence, self-inductance becomes four times.
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