A) 0.1 mm/s
B) 0.2mm/s
C) 0.3 mm/s
D) 0.5 mm/s
Correct Answer: A
Solution :
Drift velocity is the average velocity that a particle, such as an electron attains due to an electric field. It is given by \[{{v}_{d}}=\frac{I}{neA}\] where\[I\]is current, n the number of electrons per unit volume, e the charge and A the area. For copper atomic mass is 63, density 9 g/ \[c{{m}^{3}}\] \[n=\frac{9}{63}\times {{N}_{A}}\] where\[{{N}_{A}}\]is Avogadros number. Given,\[I=1.1\text{ }A,\text{ }r=0.5\times {{10}^{-1}}cm\] \[\therefore \]\[{{v}_{d}}=\frac{1.1\times 63\times 100}{9\times 6\times {{10}^{23}}\times 1.6\times {{10}^{-19}}\times 3.14}\] \[\times 0.5\times 0.5\] \[\Rightarrow \] \[{{v}_{d}}=0.0102cm/s=0.1\,mm/s\]
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