A) increases
B) decreases
C) remains same
D) none of these
Correct Answer: A
Solution :
\[NaCl\underset{S}{\mathop{N{{a}^{+}}}}\,+\underset{S}{\mathop{C{{l}^{-}}}}\,\] \[HCl\underset{{{S}_{1}}}{\mathop{{{H}^{+}}}}\,+\underset{{{S}_{1}}}{\mathop{C{{l}^{-}}}}\,\] The solubility of\[C{{l}^{-}}\]becomes\[S+{{S}_{1}}\]. The concentration of\[C{{l}^{-}}\]ion increases, hence the ionic product of\[NaCl\]also increases.
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