A) \[55.5\times 6.023\times {{10}^{23}}\]
B) \[18\times 6.023\times {{10}^{23}}\]
C) \[18\div 22.4\times {{10}^{23}}\]
D) \[1.8\times {{10}^{23}}\]
Correct Answer: A
Solution :
\[1\text{ }L\text{ }{{H}_{2}}O=1000\text{ }cc=1000\text{ }g\] \[\therefore \] 18 g of\[{{H}_{2}}\text{O}=6.023\times {{10}^{23}}\]molecules \[\therefore \]1000 g of \[{{H}_{2}}O=\frac{6.023\times {{10}^{23}}\times 1000}{18}\]\[=6.023\times {{10}^{23}}\times 55.5\]molecules
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