A) an isobar of X
B) an isotope of X
C) an isotone of X
D) X itself
Correct Answer: B
Solution :
\[_{A}{{X}^{M}}{{\xrightarrow[{}]{\alpha }}_{A-2}}{{X}^{M-4}}{{\xrightarrow[{}]{\beta }}_{A-1}}{{X}^{B-4}}\]\[{{\xrightarrow[{}]{\beta }}_{A}}{{X}^{B-4}}\] Hence, resulting element will be an isotope of X because both have same atomic number.
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