J & K CET Medical J & K - CET Medical Solved Paper-2000

  • question_answer
    At 298 K, the standard reduction potentials for the following half reactions are given as:
    \[Z{{n}^{2+}}+2{{e}^{}}\xrightarrow{{}}Zn(s)\]                         \[\,0.762\]
    \[C{{r}^{3+}}(aq)+3{{e}^{}}\xrightarrow{{}}Cr(s)\]                                 \[\,0.740\]
    \[2{{H}^{+}}(aq)+2{{e}^{}}\xrightarrow{{}}{{H}_{2}}(g)\]                      \[0.00\]
    \[F{{e}^{3+}}(aq)+3{{e}^{}}\xrightarrow{{}}Fe(aq)\]                   \[+\,0.770\]
    The strongest reducing agent is:

    A)  Zn (s)                                   

    B)  H (s)

    C)  Cr (s)                                   

    D)  Fe (s)

    Correct Answer: A

    Solution :

    \[Z{{n}^{2+}}+2{{e}^{-}}\xrightarrow{{}}Zn;\] \[{{E}^{o}}=-\,0.762\]
    \[C{{r}^{3+}}+3{{e}^{-}}\xrightarrow{{}}Cr;\] \[{{E}^{o}}=-\,0.740\]
    \[2{{H}^{+}}+2{{e}^{-}}\xrightarrow{{}}{{H}_{2}};\] \[{{E}^{o}}=0.00\]
    \[F{{e}^{3+}}+3{{e}^{-}}\xrightarrow{{}}Fe;\] \[{{E}^{o}}=+0.770\]
    The substances which have lower reduction potential are stronger reducing agents. Here, the reduction potential of zinc is lowest hence, it is the strongest reducing agent.


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