A) Mg oxidises Fe
B) Zn oxidises Fe
C) Zn reduces\[M{{g}^{2+}}\]
D) Zn reduces\[F{{e}^{2+}}\]
Correct Answer: D
Solution :
\[M{{g}^{2+}}+2{{e}^{-}}\xrightarrow{{}}Mg;\] \[{{E}^{o}}=-2.37\,V\] \[Z{{n}^{2+}}+2{{e}^{-}}\xrightarrow{{}}Zn;\] \[{{E}^{o}}=-\,0.76\,V\] \[F{{e}^{2+}}+2{{e}^{-}}\xrightarrow{{}}Fe;\] \[{{E}^{o}}=-\,0.44\,V\] The reduction potential of\[Z{{n}^{2+}}/Zn\]is lower than\[F{{e}^{2+}}/Fe,\]hence, zinc can reduce\[F{{e}^{2+}}\]. \[Zn+F{{e}^{2+}}\xrightarrow{{}}Z{{n}^{2+}}+Fe\]
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