J & K CET Engineering J and K - CET Engineering Solved Paper-2015

  • question_answer
    For a reaction \[\text{2A}\xrightarrow{\text{3B}}\text{3B;}\]if the rate of formation of B is\[x\,\text{mol/L,}\]the rate of consumption of A is

    A) \[x\]

    B)  \[\frac{3x}{2}\]

    C)  \[\frac{2x}{3}\]

    D)  \[3x\]

    Correct Answer: C

    Solution :

     For reaction, \[2A\xrightarrow{{}}3B\] \[\therefore \] \[-\frac{1}{2}\frac{d[A]}{dt}=\frac{1}{3}\frac{d[B]}{dt}\] Given, \[\frac{d[B]}{dt}=xmol/L\] \[\therefore \] \[\frac{d[A]}{dt}=-\frac{2}{3}\frac{d[B]}{dt}=-\frac{2}{3}x\] Hence, rate of consumption of A \[\left[ \frac{d[A]}{dt} \right]=\frac{2}{3}x\]


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