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J & K CET Engineering J and K - CET Engineering Solved Paper-2014

  • question_answer
    A crane lifts weight of \[75\text{ }kg\]to a height of \[15\text{ }m\] in\[15\text{ }s\]. The power of the crane is (assuming \[g=9.8\,m/{{s}^{2}}\])

    A)  \[635\,\,W\]           

    B)  \[735\,\,W\]

    C)  \[835\,\,W\]           

    D)  \[1135\,\,W\]

    Correct Answer: B

    Solution :

    Work done by lift = change in PE of weight \[=mgh\] \[=750\times 9.8\times 15=11025\,\,J\] So power of crane \[=\frac{Energy\,used}{time}\] \[=\frac{11025}{15}=735\,W\]


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