A) \[{{54}^{o}}C\]
B) \[{{327}^{o}}C\]
C) \[{{1200}^{o}}C\]
D) \[{{927}^{o}}C\]
Correct Answer: D
Solution :
Mean velocity of gas molecules \[v=\sqrt{\frac{8RT}{\pi T}}\] \[v\propto \sqrt{T}\] \[\frac{{{v}_{1}}}{{{v}_{2}}}=\sqrt{\frac{{{T}_{1}}}{{{T}_{2}}}}\] \[\frac{{{v}_{1}}}{{{v}_{2}}}=\sqrt{\frac{300}{{{T}_{2}}}}\] \[\frac{{{v}_{1}}}{2{{v}_{1}}}=\sqrt{\frac{300}{{{T}_{2}}}}\] \[\frac{1}{4}=\frac{300}{{{T}_{2}}}\] \[{{T}_{2}}=1200\,K=1200-273\] \[={{927}^{o}}C\]
You need to login to perform this action.
You will be redirected in
3 sec
