A) 180
B) 160
C) 16
D) 100
Correct Answer: B
Solution :
\[p=p_{A}^{o}\left( \frac{{{n}_{A}}}{{{n}_{A}}+{{n}_{B}}} \right)+p_{B}^{o}\left( \frac{{{n}_{B}}}{{{n}_{A}}+{{n}_{B}}} \right)\] \[184=200\left( \frac{3}{3+2} \right)+p_{B}^{o}\left( \frac{2}{3+2} \right)\] \[184=200\times \frac{3}{5}+p_{B}^{o}\times \frac{2}{5}\] \[184=120+p_{B}^{o}\frac{2}{5}\] \[64=p_{B}^{o}\frac{2}{5}\] \[p_{B}^{o}=\frac{64\times 5}{2}=160\,\text{Torr}\]
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