J & K CET Engineering J and K - CET Engineering Solved Paper-2004

  • question_answer
    The activation energy for most of the reactions is approximately \[50\,\text{kJ}\,\text{mo}{{\text{l}}^{-1}}.\] The value of temperature coefficient for such reactions is

    A) \[~>2\]          

    B) \[~>3\]

    C) \[~<\,\,1\]           

    D) \[~>4\]

    Correct Answer: A

    Solution :

     The temperature coefficient is the ratio of two velocity constants having the difference of \[\text{10}{{\,}^{\text{o}}}\text{C}\text{.}\] Temperature coefficient \[=\frac{{{k}_{t}}+10}{{{k}_{t}}}\] For most of the reaction its value lies between 2 and 3.


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