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J & K CET Engineering J and K - CET Engineering Solved Paper-2004

  • question_answer
    In Young's double slit experiment the amplitudes of two sources are \[3a\]and a respectively. The ratio of intensities of bright  and dark fringes will be                   

    A)  \[3:1\]

    B)  \[4:1\]

    C)  \[2:1\]

    D)  \[9:1\]

    Correct Answer: B

    Solution :

    For bright fringe, the resultant amplitude is  given by                                   \[=3a+a=4a\] For dark fringe the resultant amplitude is given by \[=3a-a=2a\] \[\therefore \]  \[Since,\text{ }intensity=K\text{ (}amplitude{{)}^{2}}\] \[\therefore \] \[\frac{{{I}_{\max }}}{{{I}_{\min }}}=\frac{{{(4a)}^{2}}}{{{(2a)}^{2}}}=\frac{4}{1}\]


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