A) increases
B) decreases
C) remains unchanged
D) becomes zero
Correct Answer: A
Solution :
The energy which is stored in the condenser is given by \[E=\frac{1}{2}.\frac{{{q}^{2}}}{C}\] ?..(i) where q is charge and C the capacitance. Also, \[C=\frac{{{\varepsilon }_{0}}A}{d}\] ??(ii) From Eqs. (i) and (ii), we get \[E=\frac{1}{2}.\frac{{{q}^{2}}d}{{{\varepsilon }_{0}}A}\] \[\Rightarrow \] \[E\,\,\alpha \,\,d\] When plate separation is increased energy increases.
You need to login to perform this action.
You will be redirected in
3 sec
