A) \[[M{{L}^{-2}}{{T}^{-3}}]\]
B) \[[M{{L}^{2}}{{T}^{-1}}]\]
C) \[[ML{{T}^{-2}}]\]
D) \[[M{{L}^{-2}}{{T}^{-1}}]\]
Correct Answer: B
Solution :
away from the coil (Lenz's law). Hence, acceleration of the falling magnet is less than g.
From Planck's law, energy of a photon of frequency v is given by \[E=hv\] where h is Planck's constant. \[\therefore \] Dimensions of \[h=\frac{Dimensions\text{ }of\text{ E}}{Dimensions\text{ }of\text{ v}}\] Dimensions of \[h=\frac{[M{{L}^{2}}{{T}^{-2}}]}{[{{T}^{-1}}]}\] \[[M{{L}^{2}}{{T}^{-1}}]\]
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