A) \[\Delta H\] is\[+\,ve;\Delta S\] is also \[+\,ve\]
B) \[\Delta H\]is\[~-ve;\text{ }\Delta S\] is also \[-ve\]
C) \[\Delta H\]is \[-ve;\Delta \,S\]is \[+\,ve\]
D) \[\Delta H\] is \[+\,ve;\Delta S\]is \[-ve\]
Correct Answer: D
Solution :
When \[\Delta G\]is\[\text{+}\,\text{ve,}\]then reaction is not possible. \[\Delta G=\Delta H-T.\Delta S\] If \[\Delta H=+\,ve\]and \[\Delta S=+\,ve,\]then \[\Delta G=+\,ve\]only when \[\Delta H>T.\Delta S\] but if\[\Delta H=+\,ve\] and\[\Delta S=-\,ve,\] then\[\Delta G=+\,ve.\]
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