A) \[2.09h\]
B) \[15.6h\]
C) \[20.9h\]
D) \[156h\]
Correct Answer: C
Solution :
Decay constant \[(\lambda )=\frac{0.693}{{{t}_{1/2}}}=\frac{0.693}{9}\] \[\lambda =\frac{2.303}{t}\log \frac{{{N}_{0}}}{N}\] \[\frac{0.693}{9}=\frac{2.303}{t}\log \frac{1}{0.2}\] \[t=20.9h\]
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