A) \[28.6\]
B) \[71.7\]
C) \[35.4\]
D) \[64.2\]
Correct Answer: B
Solution :
% of chlorine \[=\frac{35.5}{143.5}\times \frac{mass\,\,of\,AgCl}{mass\,of\,the\,compound}\times 100\] \[=\frac{35.5}{143.5}\times \frac{0.287}{0.099}\times 100\] \[=71.71%\]
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