Haryana PMT Haryana PMT Solved Paper-2008

  • question_answer
    A black body at \[1227{}^\circ C\] emits radiations with maximum intensity at a wavelength of \[5000\overset{\text{o}}{\mathop{\text{A}}}\,\]. If the temperature of the body is increased by  \[1000{}^\circ C\], the maximum intensity will be observed at

    A) \[4000\overset{\text{o}}{\mathop{\text{A}}}\,\]

    B) \[5000\overset{\text{o}}{\mathop{\text{A}}}\,\]

    C) \[6000\overset{\text{o}}{\mathop{\text{A}}}\,\]

    D) \[3000\overset{\text{o}}{\mathop{\text{A}}}\,\]

    Correct Answer: D

    Solution :

                    According to Wiens law \[{{\lambda }_{m}}T\]= constant (say b) where \[{{\lambda }_{m}}\] is wavelength corresponding to maximum intensity of radiation and T is temperature of the body in Kelvin. \[\therefore \]  \[\frac{\lambda {{}_{m}}}{{{\lambda }_{m}}}=\frac{T}{T}\] Given,   \[T=1227+273=1500K\]                 \[T=1227+1000+273=2500K\]                 \[{{\lambda }_{m}}=5000\overset{\text{o}}{\mathop{\text{A}}}\,\] Hence,   \[\lambda {{}_{m}}=\frac{1500}{2500}\times 5000=3000\overset{\text{o}}{\mathop{\text{A}}}\,\]


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