A) More frequency, less wavelength
B) More frequency, more wavelength
C) Less frequency, less wavelength
D) More frequency, constant wavelength
Correct Answer: A
Solution :
Key Idea When the distance between the source and listener is decreasing, the apparent frequency increases. According to Dopplers effect,, whenever there is a relative motion between a source of sound and listener, the apparent frequency of sound heard by the listener is different from the actual frequency of sound emitted by the source. Let S be source sound and L the listener of sound. Let v be the actual 8 frequency of sound emitted by the source and \[\lambda \] be the actual wavelength of the sound emitted. If v is velocity of sound in still air, then \[\lambda =\frac{v}{v}\] If velocity of listener is \[{{v}_{L}}\] and velocity of source is v^, then apparent frequency of sound waves heard by the listener is \[v=\frac{v-{{v}_{L}}}{v-{{v}_{S}}}\times v\] Here, both source and listener are approaching each other. Then \[{{v}_{s}}\] is positive and \[{{v}_{L}}\] is negative. \[\therefore \] \[v=\frac{v-(-{{v}_{L}})}{v-{{v}_{S}}}v\] \[\left( \frac{v+{{v}_{L}}}{v-{{v}_{S}}} \right)v\] i.e., \[v>v\] Also, \[\lambda <\lambda \] So, listener, listens more frequency and observes less wavelength.You need to login to perform this action.
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