A) \[CO,C{{O}_{2}}\]
B) \[C{{O}_{2}},CO\]
C) \[C{{H}_{4}},{{C}_{2}}{{H}_{6}}\]
D) \[CC{{l}_{4}},CHC{{l}_{3}}\]
Correct Answer: B
Solution :
Red hot coke acts as a reducing agent and reduces \[\text{C}{{\text{O}}_{2}}\]to CO. \[\underset{A}{\mathop{C{{O}_{2}}}}\,+\underset{\text{(red}\,\text{hot)}}{\mathop{C}}\,\xrightarrow{{}}\underset{B}{\mathop{2CO}}\,\]
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