A) Nitrogen
B) Carbon
C) Fluorine
D) Sulphur
Correct Answer: D
Solution :
Eq. Weight of element \[\text{= }\frac{\text{Weight}\,\text{of}\,\text{element}}{\text{Weiight}\,\text{of}\,\text{oxygen}}\text{ }\!\!\times\!\!\text{ 8}\] \[=\frac{0.14}{0.28-0.14}\times 8=8{{g}^{g-equiv}}\] Thus, the element should be suphur as its eq. Weight can be 8. \[\underset{\begin{smallmatrix} \text{1}\,\text{mol} \\ \text{32}\,\text{g} \end{smallmatrix}}{\mathop{\text{S}}}\,+{{O}_{2}}\xrightarrow{{}}\underset{\begin{smallmatrix} \text{1}\,\text{mol} \\ \text{32 + (2}\,\times \,\,16\text{)}\,\,\text{=}\,\,\text{64}\,\text{g} \end{smallmatrix}}{\mathop{S{{O}_{2}}}}\,\] \[\because \] 32 g sulphur, on combustion, gives oxide \[=64\text{ }g\] \[\because \]0.14 g sulphur, on combustion, will give oxide \[=\frac{64\times 0.14}{32}=0.28g\] Hence, it is confirmed that the element is sulphur.
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