question_answer

The correct order of magnitude of bond angles among the compounds \[C{{H}_{4}},N{{H}_{3}}\] and \[{{\text{H}}_{\text{2}}}\text{O}\] is

A)  \[C{{H}_{4}}<{{H}_{2}}O<N{{H}_{3}}\]

B)  \[{{H}_{2}}O<N{{H}_{3}}<C{{H}_{4}}\]

C)  \[N{{H}_{3}}<C{{H}_{4}}<{{H}_{2}}O\]

D)  \[N{{H}_{3}}<{{H}_{2}}O<C{{H}_{4}}\]

Correct Answer: B

Solution :

                 Bond angles depend upon number of lone pair (s) of electrons. Higher the number of lone pairs of electrons, lesser the bond angle.