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EAMCET Medical EAMCET Medical Solved Paper-2009

  • question_answer
    A theatre of volume \[100\times 40\times 10\text{ }{{m}^{3}}can\]accommodate 1000 visitors. The reverberation time of the theatre when empty is 8.5 s. If the theatre is now filled with 500 visitors, occupying the front-half seats, the reverberation time changes to 6-2 s. The average absorption coefficient of each visitor is nearly

    A)  0.6                                        

    B)  0.5

    C)  0.45                                      

    D)  0.7

    Correct Answer: D

    Solution :

     Number of visitors = 1000 Volume of theatre \[=\text{ }100\text{ }\times \text{ }40\text{ }\times \text{ }10\text{ }c{{m}^{3}}\] In first case: Volume acquired by one visitor \[=\frac{100\times 40\times 10}{1000}\] \[=40\,{{m}^{3}}\] Reverberation time = 8.5 s In second case: Volume acquired by one visitor \[=\frac{100\times 40\times 10}{500}\]\[=80\,{{m}^{3}}\] Reverberation time = 6.2 s The average absorbtion coefficient \[\eta =\frac{40\times 8.5}{80\times 6.2}=\frac{85}{124}\]\[\approx (0.7)\]


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