A) \[33.33{}^\circ C\]
B) \[56.67{}^\circ C\]
C) \[77.66{}^\circ C\]
D) \[30{}^\circ C\]
Correct Answer: B
Solution :
Let \[t{{\,}^{o}}C\]be the temperature of the mixture. From Calorimetry principle, Heat given by 10 g of water = Heat taken by 5 g of water or \[{{m}_{1}}{{s}_{w}}\Delta {{T}_{1}}={{m}_{2}}{{s}_{w}}\Delta T\] \[\therefore \] \[10\times (70-t)=5\times (t-30)\] \[\therefore \] \[t=56.67{{\,}^{o}}C\]
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