A) \[19.3\times {{10}^{4}}\]
B) \[17.8\times {{10}^{4}}\]
C) \[24.93\times {{10}^{9}}\]
D) \[17.8\times {{010}^{8}}.\]
Correct Answer: B
Solution :
Most probable velocity \[=\sqrt{\frac{8RT}{\pi m}}\] \[T=(27+273)=300\,K\] Molecular mass of \[{{H}_{2}}=2g\text{ }mo{{l}^{-1}}\] Most probable velocity \[({{H}_{2}})\] \[=\sqrt{\frac{8\times 8.314\times {{10}^{7}}\times 300}{3.14\times 2}}\] \[=17.8\times {{10}^{4}}cm/s.\]
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