A) \[5\times {{10}^{-12}}\text{M}\]
B) \[2\times {{10}^{-3}}\text{M}\]
C) \[1\times {{10}^{-14}}\text{M}\]
D) none of the above
Correct Answer: A
Solution :
Since, it is a weak acid, the equation to calculate \[[{{H}^{+}}]\]is \[C\times \alpha \] (\[\alpha =%\]of ionisation) \[=0.1\times 0.02=2\times {{10}^{-3}}\text{M}\] \[{{K}_{w}}=[{{H}^{+}}][O{{H}^{-}}]\] \[[O{{H}^{-}}]=\frac{{{K}_{w}}}{[{{H}^{+}}]}=\frac{1\times {{10}^{-14}}}{2\times {{10}^{-3}}}=0.5\times {{10}^{-12}}\,M\]
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