EAMCET Medical EAMCET Medical Solved Paper-2006

  • question_answer
    The first emission line on hydrogen atomic spectrum in the Balmer series appears at (R = Rydberg constant).

    A)  \[\frac{5R}{36}c{{m}^{-1}}\]                      

    B)  \[\frac{3R}{4}c{{m}^{-1}}\]

    C)  \[\frac{7R}{144}c{{m}^{-1}}\]                    

    D)  \[\frac{9R}{400}c{{m}^{-1}}\]

    Correct Answer: A

    Solution :

                     Rydberg Ritz equation is \[v=R\left[ \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right]\] Where \[{{n}_{1}}=2,\,{{n}_{2}}=3\] \[R\left[ \frac{9-4}{36} \right]=\frac{5R}{36}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner