A) 1 : 6
B) 2 : 3
C) 3 : 2
D) 6 : 1
Correct Answer: D
Solution :
The coefficient of restitution \[e=\left( \frac{Velocity\,of\,separation}{Velocity\,of\,approach} \right)\] \[\therefore \] \[{{e}_{1}}=\frac{{{({{v}_{separation}})}_{1}}}{{{({{v}_{apporach}})}_{1}}}=\frac{1}{2}\] and \[{{e}_{2}}=\frac{{{({{v}_{separation}})}_{2}}}{{{({{v}_{apporach}})}_{2}}}\] but \[\frac{{{e}_{1}}}{{{e}_{2}}}=\frac{3}{1}\] \[\Rightarrow \] \[\frac{{{e}_{2}}}{{{e}_{1}}}=\frac{1}{3}\] \[\therefore \] \[\frac{{{({{v}_{separation}})}_{2}}}{{{({{v}_{apporach}})}_{2}}}=\frac{1}{2}\times \frac{1}{3}\] \[\Rightarrow \] \[\frac{{{({{v}_{separation}})}_{2}}}{{{({{v}_{apporach}})}_{2}}}=\frac{6}{1}\]
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