A) \[N,O,F,Ne\]
B) \[N{{a}^{+}},M{{n}^{2+}},A{{l}^{3+}},S{{i}^{4+}}\]
C) \[C{{l}^{-}},Ar,C{{a}^{2+}},T{{i}^{4+}}\]
D) \[Be,M{{g}^{2+}},Ca,S{{i}^{2+}}\]
Correct Answer: C
Solution :
Cl (at. No. = 17) \[\text{C}{{\text{l}}^{-}}\](no. of electrons = 18) Ar (at. no. = 18) (no. of electrons = 18) Ca (at. no. = 20) \[\text{C}{{\text{a}}^{2+}}\]no. of electrons = 18 Ti (at. no. = 22) \[\text{T}{{\text{i}}^{\text{4+}}}\]no. of electrons = 18 \[\therefore \] All these are isoelectronic.
You need to login to perform this action.
You will be redirected in
3 sec
