A) \[NaCl\]
B) \[CuCl\]
C) \[CuC{{l}_{2}}\]
D) \[CsSl\]
Correct Answer: C
Solution :
According to Fajans rule, as the size of cation. decreases, its polarising power increases. Hence, \[\text{C}{{\text{u}}^{\text{2+}}}\] polarise \[\text{C}{{\text{l}}^{-}}\] ions more than \[\text{C}{{\text{u}}^{\text{+}}}\text{.}\] Therefore, \[\text{CuC}{{\text{l}}_{2}}\] has more covalent character and hence, its boiling point is less.
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