A) \[{{S}_{N}}1\]mechanism
B) \[{{S}_{N}}2\]mechanism
C) any of and
D) none of the above
Correct Answer: A
Solution :
Tertiary halide preferentially undergo \[{{\text{S}}_{\text{N}}}\text{1}\] substitution as they can give stable carbocation. \[\underset{\text{t}-\text{butyl}\,\text{chloride}}{\mathop{{{\text{H}}_{3}}C-\underset{C{{H}_{3}}}{\overset{C{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-Cl}}\,\xrightarrow[-Cl]{slow}\underset{\text{Carbocation}}{\mathop{{{({{H}_{3}}C)}_{3}}{{C}^{+}}}}\,\xrightarrow[fast]{+O{{H}^{-}}}\]
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