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EAMCET Medical EAMCET Medical Solved Paper-2006

  • question_answer
    A 0 5 g/L solution of glucose is found to be isotonic with a 2.5 g/L solution of an organic compound. What will be the molecular weight of that organic compound?    

    A)  300                                       

    B)  600

    C)  900                                       

    D)  200

    Correct Answer: C

    Solution :

                     Molarity of glucose solution\[=\frac{0.5g}{180\times 1L}=0.0027\,M\] Isotonic   solution   have   equal   molar concentrations, hence, molarity of organic compound solution = 0.0027 M \[\therefore \] Molecular weight of compound\[=\frac{2.5}{0.0027\times 1}=900\]


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