A) 125
B) 1250
C) 200
D) 20
Correct Answer: D
Solution :
\[\text{KMn}{{\text{O}}_{\text{4}}}\]reacts with oxalic acid according to the following equation. \[2MnO_{4}^{-}+5{{C}_{2}}O_{4}^{2-}+16{{H}^{+}}\to 2M{{n}^{2+}}\] \[+10C{{O}_{2}}+8{{H}_{2}}O\] Eq. mass of \[KMn{{O}_{4}}=\frac{\text{mol}\text{.mass}}{7-2}\] \[{{N}_{KMn{{O}_{4}}}}=5\times molarity=5\times {{10}^{-4}}\] Eq. mass of \[{{C}_{2}}O_{4}^{2-}=\frac{\text{mol}\text{.mass}}{2(4-3)}=\frac{\text{mol}\text{.mass}}{2}\] \[{{N}_{C{{ & }_{2}}O_{4}^{2-}}}=2\times molarity\] \[=2\times {{10}^{-2}}\] \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] \[5\times {{10}^{-4}}\times {{V}_{1}}=2\times {{10}^{-2}}\times 0.5\] \[{{V}_{1}}=\frac{2\times {{10}^{-2}}\times 0.5}{5\times {{10}^{-4}}}=20L\]
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