EAMCET Medical EAMCET Medical Solved Paper-2006

  • question_answer
    Consider the following reactions : (i) \[Al+NaOH+{{H}_{2}}O\xrightarrow{\Delta }\] (ii) \[{{F}_{2}}+NaOH(conc.)\xrightarrow{{}}\] (iii) \[NaOH+P(white)+{{H}_{2}}O\xrightarrow{{}}\] The correct set of reactions which give gaseous product is

    A)  I, II and III          

    B)  only I and II

    C)  only I and III    

    D)  only II and III

    Correct Answer: A

    Solution :

                     \[2Al+2NaOH+2{{H}_{2}}O\to \underset{\text{sod}\text{.meta}\,\text{aluminate}}{\mathop{2NaAl{{O}_{2}}}}\,+{{H}_{2}}\]\[2{{F}_{2}}+2NaOH(conc.)\xrightarrow{{}}{{O}_{2}}+4NaF+2{{H}_{2}}O\]\[\underset{(white)}{\mathop{{{P}_{4}}}}\,+3NaOH+3{{H}_{2}}O\to \underset{\text{Sod}\text{.}\,\text{hypophosphite}}{\mathop{3Na{{H}_{2}}P{{O}_{2}}}}\,+\underset{\text{Phosphene}}{\mathop{P{{H}_{3}}}}\,\]So, all the three reactions give gaseous products.


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