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EAMCET Medical EAMCET Medical Solved Paper-2006

  • question_answer
    Observe the following reaction : \[A(g)+3B(g)\xrightarrow{{}}2C(g)\] The rate of this reaction \[\left( -\frac{d[A]}{dt} \right)\]  is \[3\times {{10}^{-3}}\,\text{mol}\,{{\text{L}}^{-1}}.\] What is the value of\[-\frac{d[B]}{dt}\]in \[\text{mol}\,{{\text{L}}^{-1}}{{\min }^{-1}}.\]?

    A)  \[3\times {{10}^{-3}}\]                 

    B)  \[9\times {{10}^{-3}}\]

    C)  \[{{10}^{-3}}\]                                 

    D)  \[1.5\times {{10}^{-3}}\]

    Correct Answer: B

    Solution :

                     The rationalised rate =\[\frac{-d[A]}{dt}=-\frac{1}{3}\frac{d[B]}{dt}=\frac{1}{2}\frac{d[C]}{dt}\] From this relation we have \[\frac{-d[B]}{dt}=-3\times \frac{d[A]}{dt}\]\[=-3\times 3\times {{10}^{-3}}=9\times {{10}^{-3}}\]


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