A) \[{{K}_{c}}=\frac{{{[A]}^{1/2}}{{[B]}^{1/3}}}{{{[C]}^{3/2}}}\]
B) \[{{K}_{c}}=\frac{{{[C]}^{3/2}}}{[{{A}^{2}}][{{B}^{3}}]}\]
C) \[{{K}_{c}}=\frac{{{[C]}^{2/3}}}{{{[A]}^{1/2}}{{[B]}^{1/3}}}\]
D) \[{{K}_{c}}=\frac{{{[C]}^{2/3}}}{{{[A]}^{1/2}}+{{[B]}^{1/3}}}\]
Correct Answer: C
Solution :
\[\frac{1}{2}A(g)+\frac{1}{2}B(g)\overset{T(K)}{\mathop{=}}\,\frac{2}{3}C(g)\] Equilibrium constant \[{{\text{K}}_{\text{c}}}\text{=}\frac{\text{Rate}\,\text{of}\,\text{product}}{\text{Rate}\,\text{of}\,\text{reactant}}\] \[{{K}_{c}}=\frac{{{[C]}^{2/3}}}{{{[A]}^{1/2}}{{[B]}^{1/3}}}\]
You need to login to perform this action.
You will be redirected in
3 sec
