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EAMCET Medical EAMCET Medical Solved Paper-2006

  • question_answer
    A teacher asked a student to connect N cells each of emf e in series to get a total emf of Ne. While connecting, the student, by mistake, reversed by polarity of n cells. The total emf of the resulting series combination is:

    A)  \[e\left( N-\frac{n}{2} \right)\]                                

    B)  \[e\left( N-n \right)\]

    C)  \[e\left( N-2n \right)\]                                

    D)  \[eN\]

    Correct Answer: C

    Solution :

                     If polarity of n cells out of N cells is reversed, then equivalent emf \[=(N-2n)e\]


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