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EAMCET Medical EAMCET Medical Solved Paper-2006

  • question_answer
    A uniform string of length 1.5 m has two successive harmonics of frequencies 70 Hz and 84 Hz. The speed of the wave in the string \[(in\text{ }m{{s}^{-1}})\] is:

    A)  84                                         

    B)  42

    C)  21                                         

    D)  10.5

    Correct Answer: B

    Solution :

                     Fundamental frequency of string  \[\text{= GCF}\]of the successive harmonics of frequencise 70 Hz and 84 Hz  \[\therefore \] \[n=14\,Hz\] \[\Rightarrow \]               \[\frac{v}{2l}=1.4\] \[\Rightarrow \]               \[v=2\times 1.5\times 14\]                 \[=42\,m/s\]


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