EAMCET Medical EAMCET Medical Solved Paper-2006

  • question_answer
    Match the following :
    List- I List- II
    A Chargaff 1 Wilkin and Franklin
    B Replicon 2 Uptake of lactose
    C Permease 3 hn RNA
    D Split gene 4 Length of DNA
    E X- ray  diffraction studies 5 (A + G) = (C + T)

    A) A-5         B-4         C-2         D-3         E-1

    B) A-5         B-4         C-1         D-3         E-2

    C) A-5         B-4         C-2         D-1         E-3

    D) A-5         B-1         C-2         D-3         E-4

    Correct Answer: A

    Solution :

                     E. Chargaff (1950) demonstrated that in DNA the numbes of adenine and thymine groups are always equal and so the number of guanine and cytosine also. - Wilkins and his associate Franklin managed to prepare highly oriented DNA fibres that allowed them to obtain an X-ray diffraction photograph. - DNA replication in prokaryotes and eukaryotes is attained in discrete units called replicons. The number of replicons depend on length of genome. - Split genes are those genes which possess non-functional genes among functional genes. The non-functional are called introns whereas the functional one as exons. The enzyme permease (glactoside permease) is a plasma-membrane bound protein that facilitates the entrance of lactose into the cell.


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