A) \[Ni/{{H}_{2}}\]
B) \[LiAl{{H}_{4}}\]
C) \[{{I}_{2}}NaOH\]
D) \[Zn-Hg/conc.HCl\]
Correct Answer: D
Solution :
Clemmensens reduction (conc. \[\text{HCl/Zn}-\text{Hg}\]) or Wolf-Kishner reduction \[({{C}_{2}}{{H}_{5}}ONa/N{{H}_{2}}N{{H}_{2}})\] can be used to convert \[\text{C=O}\]group into \[\text{C}{{\text{H}}_{\text{2}}}\]group \[\underset{\begin{smallmatrix} \text{Aldehyde}\,\text{or} \\ \text{ketone} \end{smallmatrix}}{\mathop{\begin{matrix} R \\ R \\ \end{matrix}C=O}}\,\xrightarrow[conc.HCl]{Zn-Hg}\underset{hydrocarbon}{\mathop{\begin{matrix} R \\ R \\ \end{matrix}C{{H}_{2}}}}\,\]
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