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EAMCET Medical EAMCET Medical Solved Paper-2005

  • question_answer
    \[\text{X}\] reacts with aqueous \[\text{NaOH}\] solution to form Y and \[{{\text{H}}_{\text{2}}}\]. Aqueous solution of Y is heated to 323-333 K and on passing \[C{{O}_{2}}\]into it, \[\text{N}{{\text{a}}_{\text{2}}}\text{C}{{\text{O}}_{\text{3}}}\] and Z were formed. When Z is heated to \[\text{1200}{{\text{ }}^{\text{o}}}\text{C,}\] At \[\text{A}{{\text{l}}_{\text{2}}}{{\text{O}}_{\text{3}}}\] is formed. X, Y and Z respectively are:

    A)  \[Al,AlC{{l}_{3}},NaAl{{O}_{2}}\]

    B)  \[Zn,\text{ }N{{a}_{2}}Zn{{O}_{2}},\text{ }Al{{(OH)}_{3}}\]

    C)  \[Al,Al{{(OH)}_{3}},AlC{{l}_{3}}\]

    D)  \[Al,NaAl{{O}_{2}},Al{{(OH)}_{3}}\]

    Correct Answer: D

    Solution :

                     The reactions are as follows: \[\underset{(X)}{\mathop{2Al}}\,+2NaOH+2{{H}_{2}}O\xrightarrow{{}}\underset{(Y)}{\mathop{2NaAl{{O}_{2}}}}\,\]\[+3{{H}_{2}}\uparrow \] \[2NaAl{{O}_{2}}+C{{O}_{2}}+3{{H}_{2}}O\xrightarrow{\Delta }N{{a}_{2}}C{{O}_{3}}\]\[+2Al{{(OH)}_{3}}(Z)\] \[2Al{{(OH)}_{3}}\xrightarrow{1200\,{{\,}^{o}}C}A{{l}_{2}}{{O}_{3}}+3{{H}_{2}}O\]


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