A) \[{{\text{C}}_{2}}{{H}_{5}}Cl,\] anhydrous \[AlC{{l}_{3}}\]
B) \[{{C}_{2}}{{H}_{5}}Cl,\] aqueous \[AlC{{l}_{3}}\]
C) \[{{C}_{2}}{{H}_{5}}OH,\] anhydrous \[AlC{{l}_{3}}\]
D) \[{{C}_{2}}{{H}_{5}}Cl,SOC{{l}_{2}}\]
Correct Answer: A
Solution :
Friedel-Crafts reaction: This reaction is used to introduce alkyi (methyl or ethyl) group in benzene ring. In this reaction when benzene reacts with alkyi halide \[({{C}_{2}}{{H}_{5}}Cl)\] in presence of anhydrous \[\text{AlC}{{\text{l}}_{\text{3}}}\]ethyl benzene is obtained.
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